Integrand size = 29, antiderivative size = 87 \[ \int \frac {(f+g x)^2}{(d+e x)^2 \left (d^2-e^2 x^2\right )} \, dx=-\frac {(e f-d g)^2}{4 d e^3 (d+e x)^2}-\frac {(e f-d g) (e f+3 d g)}{4 d^2 e^3 (d+e x)}+\frac {(e f+d g)^2 \text {arctanh}\left (\frac {e x}{d}\right )}{4 d^3 e^3} \]
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Time = 0.07 (sec) , antiderivative size = 87, normalized size of antiderivative = 1.00, number of steps used = 4, number of rules used = 3, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.103, Rules used = {862, 90, 214} \[ \int \frac {(f+g x)^2}{(d+e x)^2 \left (d^2-e^2 x^2\right )} \, dx=\frac {\text {arctanh}\left (\frac {e x}{d}\right ) (d g+e f)^2}{4 d^3 e^3}-\frac {(3 d g+e f) (e f-d g)}{4 d^2 e^3 (d+e x)}-\frac {(e f-d g)^2}{4 d e^3 (d+e x)^2} \]
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Rule 90
Rule 214
Rule 862
Rubi steps \begin{align*} \text {integral}& = \int \frac {(f+g x)^2}{(d-e x) (d+e x)^3} \, dx \\ & = \int \left (\frac {(-e f+d g)^2}{2 d e^2 (d+e x)^3}+\frac {(e f-d g) (e f+3 d g)}{4 d^2 e^2 (d+e x)^2}+\frac {(e f+d g)^2}{4 d^2 e^2 \left (d^2-e^2 x^2\right )}\right ) \, dx \\ & = -\frac {(e f-d g)^2}{4 d e^3 (d+e x)^2}-\frac {(e f-d g) (e f+3 d g)}{4 d^2 e^3 (d+e x)}+\frac {(e f+d g)^2 \int \frac {1}{d^2-e^2 x^2} \, dx}{4 d^2 e^2} \\ & = -\frac {(e f-d g)^2}{4 d e^3 (d+e x)^2}-\frac {(e f-d g) (e f+3 d g)}{4 d^2 e^3 (d+e x)}+\frac {(e f+d g)^2 \tanh ^{-1}\left (\frac {e x}{d}\right )}{4 d^3 e^3} \\ \end{align*}
Time = 0.05 (sec) , antiderivative size = 87, normalized size of antiderivative = 1.00 \[ \int \frac {(f+g x)^2}{(d+e x)^2 \left (d^2-e^2 x^2\right )} \, dx=\frac {\frac {2 d (-e f+d g) \left (2 d^2 g+e^2 f x+d e (2 f+3 g x)\right )}{(d+e x)^2}-(e f+d g)^2 \log (d-e x)+(e f+d g)^2 \log (d+e x)}{8 d^3 e^3} \]
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Time = 0.45 (sec) , antiderivative size = 138, normalized size of antiderivative = 1.59
method | result | size |
norman | \(\frac {\frac {d^{2} g^{2}-e^{2} f^{2}}{2 d \,e^{3}}+\frac {\left (3 d^{2} g^{2}-2 d e f g -e^{2} f^{2}\right ) x}{4 d^{2} e^{2}}}{\left (e x +d \right )^{2}}-\frac {\left (d^{2} g^{2}+2 d e f g +e^{2} f^{2}\right ) \ln \left (-e x +d \right )}{8 e^{3} d^{3}}+\frac {\left (d^{2} g^{2}+2 d e f g +e^{2} f^{2}\right ) \ln \left (e x +d \right )}{8 e^{3} d^{3}}\) | \(138\) |
default | \(\frac {\left (-d^{2} g^{2}-2 d e f g -e^{2} f^{2}\right ) \ln \left (-e x +d \right )}{8 e^{3} d^{3}}-\frac {-3 d^{2} g^{2}+2 d e f g +e^{2} f^{2}}{4 d^{2} e^{3} \left (e x +d \right )}-\frac {d^{2} g^{2}-2 d e f g +e^{2} f^{2}}{4 e^{3} d \left (e x +d \right )^{2}}+\frac {\left (d^{2} g^{2}+2 d e f g +e^{2} f^{2}\right ) \ln \left (e x +d \right )}{8 e^{3} d^{3}}\) | \(148\) |
risch | \(\frac {\frac {d^{2} g^{2}-e^{2} f^{2}}{2 d \,e^{3}}+\frac {\left (3 d^{2} g^{2}-2 d e f g -e^{2} f^{2}\right ) x}{4 d^{2} e^{2}}}{\left (e x +d \right )^{2}}-\frac {\ln \left (-e x +d \right ) g^{2}}{8 e^{3} d}-\frac {\ln \left (-e x +d \right ) f g}{4 e^{2} d^{2}}-\frac {\ln \left (-e x +d \right ) f^{2}}{8 e \,d^{3}}+\frac {\ln \left (e x +d \right ) g^{2}}{8 e^{3} d}+\frac {\ln \left (e x +d \right ) f g}{4 e^{2} d^{2}}+\frac {\ln \left (e x +d \right ) f^{2}}{8 e \,d^{3}}\) | \(170\) |
parallelrisch | \(-\frac {4 d^{2} e^{2} f^{2}-4 d^{4} g^{2}-\ln \left (e x +d \right ) d^{2} e^{2} f^{2}+\ln \left (e x -d \right ) x^{2} e^{4} f^{2}-\ln \left (e x +d \right ) x^{2} e^{4} f^{2}+\ln \left (e x -d \right ) d^{2} e^{2} f^{2}-6 x \,d^{3} e \,g^{2}+2 x d \,e^{3} f^{2}+2 \ln \left (e x -d \right ) x^{2} d \,e^{3} f g -2 \ln \left (e x +d \right ) x^{2} d \,e^{3} f g +4 \ln \left (e x -d \right ) x \,d^{2} e^{2} f g -4 \ln \left (e x +d \right ) x \,d^{2} e^{2} f g -2 \ln \left (e x +d \right ) x d \,e^{3} f^{2}-2 \ln \left (e x +d \right ) d^{3} e f g +\ln \left (e x -d \right ) d^{4} g^{2}+\ln \left (e x -d \right ) x^{2} d^{2} e^{2} g^{2}-\ln \left (e x +d \right ) x^{2} d^{2} e^{2} g^{2}+2 \ln \left (e x -d \right ) x \,d^{3} e \,g^{2}+2 \ln \left (e x -d \right ) x d \,e^{3} f^{2}-2 \ln \left (e x +d \right ) x \,d^{3} e \,g^{2}+2 \ln \left (e x -d \right ) d^{3} e f g +4 x \,d^{2} e^{2} f g -\ln \left (e x +d \right ) d^{4} g^{2}}{8 d^{3} e^{3} \left (e x +d \right )^{2}}\) | \(377\) |
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Leaf count of result is larger than twice the leaf count of optimal. 271 vs. \(2 (81) = 162\).
Time = 0.31 (sec) , antiderivative size = 271, normalized size of antiderivative = 3.11 \[ \int \frac {(f+g x)^2}{(d+e x)^2 \left (d^2-e^2 x^2\right )} \, dx=-\frac {4 \, d^{2} e^{2} f^{2} - 4 \, d^{4} g^{2} + 2 \, {\left (d e^{3} f^{2} + 2 \, d^{2} e^{2} f g - 3 \, d^{3} e g^{2}\right )} x - {\left (d^{2} e^{2} f^{2} + 2 \, d^{3} e f g + d^{4} g^{2} + {\left (e^{4} f^{2} + 2 \, d e^{3} f g + d^{2} e^{2} g^{2}\right )} x^{2} + 2 \, {\left (d e^{3} f^{2} + 2 \, d^{2} e^{2} f g + d^{3} e g^{2}\right )} x\right )} \log \left (e x + d\right ) + {\left (d^{2} e^{2} f^{2} + 2 \, d^{3} e f g + d^{4} g^{2} + {\left (e^{4} f^{2} + 2 \, d e^{3} f g + d^{2} e^{2} g^{2}\right )} x^{2} + 2 \, {\left (d e^{3} f^{2} + 2 \, d^{2} e^{2} f g + d^{3} e g^{2}\right )} x\right )} \log \left (e x - d\right )}{8 \, {\left (d^{3} e^{5} x^{2} + 2 \, d^{4} e^{4} x + d^{5} e^{3}\right )}} \]
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Leaf count of result is larger than twice the leaf count of optimal. 185 vs. \(2 (75) = 150\).
Time = 0.45 (sec) , antiderivative size = 185, normalized size of antiderivative = 2.13 \[ \int \frac {(f+g x)^2}{(d+e x)^2 \left (d^2-e^2 x^2\right )} \, dx=- \frac {- 2 d^{3} g^{2} + 2 d e^{2} f^{2} + x \left (- 3 d^{2} e g^{2} + 2 d e^{2} f g + e^{3} f^{2}\right )}{4 d^{4} e^{3} + 8 d^{3} e^{4} x + 4 d^{2} e^{5} x^{2}} - \frac {\left (d g + e f\right )^{2} \log {\left (- \frac {d \left (d g + e f\right )^{2}}{e \left (d^{2} g^{2} + 2 d e f g + e^{2} f^{2}\right )} + x \right )}}{8 d^{3} e^{3}} + \frac {\left (d g + e f\right )^{2} \log {\left (\frac {d \left (d g + e f\right )^{2}}{e \left (d^{2} g^{2} + 2 d e f g + e^{2} f^{2}\right )} + x \right )}}{8 d^{3} e^{3}} \]
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Time = 0.19 (sec) , antiderivative size = 149, normalized size of antiderivative = 1.71 \[ \int \frac {(f+g x)^2}{(d+e x)^2 \left (d^2-e^2 x^2\right )} \, dx=-\frac {2 \, d e^{2} f^{2} - 2 \, d^{3} g^{2} + {\left (e^{3} f^{2} + 2 \, d e^{2} f g - 3 \, d^{2} e g^{2}\right )} x}{4 \, {\left (d^{2} e^{5} x^{2} + 2 \, d^{3} e^{4} x + d^{4} e^{3}\right )}} + \frac {{\left (e^{2} f^{2} + 2 \, d e f g + d^{2} g^{2}\right )} \log \left (e x + d\right )}{8 \, d^{3} e^{3}} - \frac {{\left (e^{2} f^{2} + 2 \, d e f g + d^{2} g^{2}\right )} \log \left (e x - d\right )}{8 \, d^{3} e^{3}} \]
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Time = 0.28 (sec) , antiderivative size = 149, normalized size of antiderivative = 1.71 \[ \int \frac {(f+g x)^2}{(d+e x)^2 \left (d^2-e^2 x^2\right )} \, dx=-\frac {{\left (e^{2} f^{2} + 2 \, d e f g + d^{2} g^{2}\right )} \log \left ({\left | -\frac {2 \, d}{e x + d} + 1 \right |}\right )}{8 \, d^{3} e^{3}} - \frac {\frac {e^{5} f^{2}}{e x + d} + \frac {d e^{5} f^{2}}{{\left (e x + d\right )}^{2}} + \frac {2 \, d e^{4} f g}{e x + d} - \frac {2 \, d^{2} e^{4} f g}{{\left (e x + d\right )}^{2}} - \frac {3 \, d^{2} e^{3} g^{2}}{e x + d} + \frac {d^{3} e^{3} g^{2}}{{\left (e x + d\right )}^{2}}}{4 \, d^{2} e^{6}} \]
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Time = 0.14 (sec) , antiderivative size = 100, normalized size of antiderivative = 1.15 \[ \int \frac {(f+g x)^2}{(d+e x)^2 \left (d^2-e^2 x^2\right )} \, dx=\frac {\frac {d^2\,g^2-e^2\,f^2}{2\,d\,e^3}-\frac {x\,\left (-3\,d^2\,g^2+2\,d\,e\,f\,g+e^2\,f^2\right )}{4\,d^2\,e^2}}{d^2+2\,d\,e\,x+e^2\,x^2}+\frac {\mathrm {atanh}\left (\frac {e\,x}{d}\right )\,{\left (d\,g+e\,f\right )}^2}{4\,d^3\,e^3} \]
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